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C-ABAPD-2507–100% Free Exam Certification Cost | the Best SAP Certified Associate - Back-End Developer - ABAP Cloud Online Lab Simulation

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SAP C-ABAPD-2507 Exam Syllabus Topics:

Topic
Details

Topic 1

Object-Oriented Design: This section of the exam measures skills of SAP ABAP Developers and covers the basics of object-oriented programming in ABAP. It includes concepts such as classes, interfaces, inheritance, polymorphism, and encapsulation, all of which are necessary for building robust and scalable ABAP applications.

Topic 2

ABAP SQL and Code Pushdown: This section of the exam measures skills of SAP ABAP Developers and covers the use of advanced SQL techniques within ABAP. It includes code pushdown strategies that leverage database-level processing to enhance application performance. Key areas include Open SQL enhancements and integrating logic closer to the database.

Topic 3

SAP Clean Core Extensibility and ABAP Cloud: This section of the exam measures skills of SAP Application Programmers and covers the clean core principles and extensibility options within SAP BTP. It also includes cloud-native ABAP development practices, emphasizing the creation of upgrade-stable and maintainable extensions aligned with SAP’s cloud strategy.

Topic 4

ABAP Core Data Services and Data Modeling: This section of the exam measures skills of SAP ABAP Developers and covers the creation, definition, and use of Core Data Services (CDS) views for data modeling within SAP environments. Candidates are expected to understand annotations, data definitions, and the role of CDS in enabling advanced data processing and integration across SAP systems.

Topic 5

Core ABAP Programming: This section of the exam measures skills of SAP Application Programmers and covers foundational ABAP programming knowledge. Topics include modularization techniques, internal tables, control structures, and classical report programming. Mastery of these concepts is essential for building efficient ABAP applications.

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q40-Q45):

NEW QUESTION # 40
You want to define the following CDS view entity with an input parameter:
Define view entity Z_CONVERT With parameters currency : ???
Which of the following can you use to replace "???? Note: There are 2 correct answers to this question.

A. built-in ABAP type
B. A component of an ABAP Dictionary structure
C. A built-in ABAP Dictionary type
D. A data element

Answer: A,D

Explanation:
The possible replacements for "???" in the CDS view entity definition with an input parameter are A. built-in ABAP type and C. A data element. These are the valid types that can be used to specify the data type of an input parameter in a CDS view entity. A built-in ABAP type is a predefined elementary type in the ABAP language, such as abap.char, abap.numc, abap.dec, etc. A data element is a reusable semantic element in the ABAP Dictionary that defines the technical attributes and the meaning of a field12. For example:
The following code snippet defines a CDS view entity with an input parameter currency of type abap.cuky, which is a built-in ABAP type for currency key:
Define view entity Z_CONVERT With parameters currency : abap.cuky as select from ... { ... } The following code snippet defines a CDS view entity with an input parameter currency of type waers, which is a data element for currency key:
Define view entity Z_CONVERT With parameters currency : waers as select from ... { ... } You cannot do any of the following:
B . A built-in ABAP Dictionary type: This is not a valid type for an input parameter in a CDS view entity. A built-in ABAP Dictionary type is a predefined elementary type in the ABAP Dictionary, such as CHAR, NUMC, DEC, etc. However, these types cannot be used directly in a CDS view entity definition. Instead, they have to be prefixed with abap. to form a built-in ABAP type, as explained above12.
D . A component of an ABAP Dictionary structure: This is not a valid type for an input parameter in a CDS view entity. A component of an ABAP Dictionary structure is a field that belongs to a structure type, which is a complex type that consists of multiple fields. However, an input parameter in a CDS view entity can only be typed with an elementary type, which is a simple type that has no internal structure12.

NEW QUESTION # 41
Given the following Core Data Service View Entity Data Definition:
1 @AccessControl.authorizationCheck: #NOT_REQUIRED
2 DEFINE VIEW ENTITY demo_flight_info_join
3 AS SELECT
4 FROM scarr AS a
5 LEFT OUTER JOIN scounter AS c
6 LEFT OUTER JOIN sairport AS p
7 ON p.id = c.airport
8 ON a.carrid = c.carrid
9 {
10 a.carrid AS carrier_id,
11 p.id AS airport_id,
12 c.countnum AS counter_number
13 }
In what order will the join statements be executed?

A. scounter will be joined to sairport first and the result will be joined with scarr.
B. scarr will be joined with sairport first and the result will be joined with scounter.
C. scarr will be joined with scounter first and the result will be joined with sairport.
D. sairport will be joined to scounter first and the result will be joined with scarr.

Answer: C

Explanation:
The order in which the join statements will be executed is:
scarr will be joined with scounter first and the result will be joined with sairport.
This is because the join statements are nested from left to right, meaning that the leftmost data source is joined with the next data source, and the result is joined with the next data source, and so on. The join condition for each pair of data sources is specified by the ON clause that follows the data source name. The join type for each pair of data sources is specified by the join operator that precedes the data source name. In this case, the join operator is LEFT OUTER JOIN, which means that all the rows from the left data source are included in the result, and only the matching rows from the right data source are included. If there is no matching row from the right data source, the corresponding fields are filled with initial values1.
Therefore, the join statements will be executed as follows:
First, scarr AS a will be joined with scounter AS c using the join condition a.carrid = c.carrid. This means that all the rows from scarr will be included in the result, and only the rows from scounter that have the same value for the carrid field will be included. If there is no matching row from scounter, the countnum field will be filled with an initial value.
Second, the result of the first join will be joined with sairport AS p using the join condition p.id = c.airport. This means that all the rows from the first join will be included in the result, and only the rows from sairport that have the same value for the id field as the airport field from the first join will be included. If there is no matching row from sairport, the id field will be filled with an initial value.

NEW QUESTION # 42
After you created a database table in the RESTful Application Programming model, what do you create next?

A. A projection view
B. A service definition
C. A metadata extension
D. A data model view

Answer: D

NEW QUESTION # 43
Which of the following is a generic internal table type?

A. STANDARD TABLE
B. SORTED TABLE
C. HASHED TABLE
D. INDEX TABLE

Answer: D

Explanation:
A generic internal table type is a table type that does not define all the attributes of an internal table in the ABAP Dictionary; it leaves some of these attributes undefined. A table type is generic in the following cases1:
You have selected Index Table or Not Specified as the access type.
You have not specified a table key or specified an incomplete table key.
You have specified a generic secondary table key.
A generic table type can be used only for typing formal parameters or field symbols. A generic table type cannot be used for defining data objects or constants2.
Therefore, the correct answer is B. INDEX TABLE, which is a generic table type that does not specify the access type or the table key. The other options are not generic table types, because:
A . SORTED TABLE is a table type that specifies the access type as sorted and the table key as a unique or non-unique primary key3.
C . STANDARD TABLE is a table type that specifies the access type as standard and the table key as a non-unique standard key that consists of all the fields of the table row in the order in which they are defined4.
D . HASHED TABLE is a table type that specifies the access type as hashed and the table key as a unique primary key5.

NEW QUESTION # 44
What are some features of ABAP SQQL? Note: There are 2 correct answers to this question.

A. It is first processed by the Database Interface.
B. It is only valid on the HANA database.
C. It is directly executed on the HANA database.
D. It is integrated in the ABAP programming language.

Answer: A,D

NEW QUESTION # 45
......

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